1-1.5x+0.5x^2=0

Solution for 1-1.5x+0.5x^2=0 equation:

1-1.5x+0.5x^2=0

a = 0.5; b = -1.5; c = +1;
Δ = b2-4ac
Δ = -1.52-4·0.5·1
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{0.25}}{2*0.5}=\frac{1.5-\sqrt{0.25}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{0.25}}{2*0.5}=\frac{1.5+\sqrt{0.25}}{1}
$